I just had a Thai national test yesterday, and I have a question about proving this.
Given seats, {}. And infinite Englishmen.
Prove that the number of ways of Englishmen sitting on the seats is , such that no two Englishmen sit in an adjacent seats (no one sitting is also counted as 1 way).
Example. (0 is vacant. 1 is occupied)
n=0; 1 way (no seats, no Englishmen)
n=1; 0 1 2 ways
n=2; 00 01 10 3 ways
n=3; 000 100 010 001 101 5 ways
n=4; 0000 1000 0100 0010 0001 1010 1001 0101 8 ways
n=5; 00000 10000 01000 00100 00010 00001 10100 10010 10001 01010 01001 00101 10101 13 ways
n=6; 000000 100000 010000 001000 000100 000010 000001 101000 100100 100010 100001 010100 010010 010001 001010 001001 000101 101010 101001 100101 010101 21 ways
etc.....
Note: is the nth Fibonacci number, for .
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I tried proving by strong induction. I can do the induction step, but I can't start the basis step. T__T
I use double counting for the induction step.
Find the number of ways given n seats
1st: nth position is vacant, (n-1) seats remaining, so there're Fn+1 ways of sitting.
2nd: nth position is occupied, so (n-1)th seat can't have anyone sitting, (n-2) seats remaining, so there're Fn ways of sitting.
Therefore, there're Fn+Fn+1=Fn+2 ways.
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Let number of ways of seating x people be Tx
To Prove:- Tn=Fn+2
Then,
Base Case: T0=F2=1,T1=F3=2
Inductive case : If true for n,n+1,
Then, Tn+Tn+1=Tn+2 ( Proved in Original Post)
Or, Tn+Tn+1=Fn+2+Fn+3=Fn+4
⇒Tn+2=Fn+4
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Thank you ^_^