Prove using "Epsilon-Delta" definition of two-sided limit:
x→3limx2=9
Definition
Let f(x) be defined for all x in some open containing the number
a with possible exception that f(x) need not to be defined at
a. We will write
x→alimf(x)=L
if given any number ϵ>0 we can find a number
δ>0 such that
∣f(x)−L∣<ϵif0<∣x−a∣<δ
#Calculus
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Comments
Like most problems, I'm doing those in a somewhat "un-orthodox" way.
Given ϵ>0. If ϵ≤1, let δ=12ϵ. Now 3−12ϵ<x<3+12ϵ implies 9−2ϵ+122ϵ2<x2<9+2ϵ+122ϵ2 so that ∣x2−9∣<ϵ as required. If ϵ>1 let δ=121.
@Otto Bretscher, @Pi Han Goh, @Calvin Lin
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Epsilon-delta definition of a limit