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This link has a lot of information on this and related problems. It gives Req=R/2 in this case, and proves it first in a simple (albeit non-rigorous) way, and then provides rigorous justification. It also gives equivalent resistances for other points A and B.
" Thus the direct link carries the same current as all the other paths, so the resistance of the direct link equals the effective resistance of the entire grid excluding that link. The direct link is in parallel with the remainder of the grid, so the combined resistance is simply R/2. " - why the resistance of the direct link is equally to the effective resistance of the entire grid EXCLUDING that link?
Let potential difference V be applied across A and B and i be the current in wires.
Assume A is isolated positive terminal, so in every direction it sends out a current of i/4 (as there are 4 directions current at a junction can take). Similarly assume B is an isolated negative terminal, so from every direction it recieves an incoming current of i/4. Therefore, in the wire between A and B, net current is i/2 from A to B and hence resistance between A and B is R(0)/2
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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http://img22.imageshack.us/img22/1256/dmj1.png
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thnks a lot! :)
This link has a lot of information on this and related problems. It gives Req=R/2 in this case, and proves it first in a simple (albeit non-rigorous) way, and then provides rigorous justification. It also gives equivalent resistances for other points A and B.
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" Thus the direct link carries the same current as all the other paths, so the resistance of the direct link equals the effective resistance of the entire grid excluding that link. The direct link is in parallel with the remainder of the grid, so the combined resistance is simply R/2. " - why the resistance of the direct link is equally to the effective resistance of the entire grid EXCLUDING that link?
Let potential difference V be applied across A and B and i be the current in wires. Assume A is isolated positive terminal, so in every direction it sends out a current of i/4 (as there are 4 directions current at a junction can take). Similarly assume B is an isolated negative terminal, so from every direction it recieves an incoming current of i/4. Therefore, in the wire between A and B, net current is i/2 from A to B and hence resistance between A and B is R(0)/2
A Twist : What if these points A and B were diagonally opposite??
irodov right??
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Yes