Explain this magic!?!?

Hello everyone!!

While researching on a series, I found something magical. Can someone explain this??

Let \[S=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+ ……\]

S=(1+13+15+)+12[1+12+13+14+]S= (1+\frac{1}{3}+\frac{1}{5}+……)+\frac{1}{2} [1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+……]

S=(1+13+15+....)+S2S=(1+\frac{1}{3}+\frac{1}{5}+....)+\frac{S}{2}

S2=1+13+15+\frac{S}{2}=1+\frac{1}{3}+\frac{1}{5}+… eqn(i)eq^{n} (i)

Now from definition of S, S2=12+14+16+.\frac{S}{2}=\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+…. eqn(ii)eq^{n} (ii)

Comparing eqn(i)eq^{n} (i) and eqn(ii)eq^{n} (ii) and transposing, We get 112+1314+..=01-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+…..=0

But obviously, (112)+(1314)+.>0(1-\frac{1}{2})+(\frac{1}{3}-\frac{1}{4})+….>0

#NumberTheory #JustForFun #Magic #InfiniteSeries

Note by Pranjal Jain
6 years, 9 months ago

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1 vote

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Comments

Here S is not a converging series. The sum of the given series diverges. So you are treating S as a number, but its sum goes to infinity ( and infinity can not be considered as number , because it does not follow the properties of numbers). So unknowingly you are applying algebraic operations on infinity (for you it is S) , which is a flaw in this your something magical. !!!!!!!!

Sandeep Bhardwaj - 6 years, 9 months ago

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Thanx dude! I got what you are saying! But I dont know much about convergence of a series! Any good and reliable source? Well, I tried to learn convergence from "Hall and Knight". I need some more help!

Pranjal Jain - 6 years, 9 months ago

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Go for some UnderGraduate Maths book about sequence and series. You will find the complete conceptual information about the convergence and divergence. Hopefully, it will help you.

Sandeep Bhardwaj - 6 years, 9 months ago
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