Fanciness!

Ok, pick a number, any number Double it. Add 9. Subtract 3. Divide by 2. Subtract your original number. Let me guess.... your answer was 3!

Here's how it works...if you turn it into an equation you should start with... let x equal your original number. Double it.-2x Add 9: 2x + 9 subtract 3: 2x + 6 divide by 2: x+3 subtract your original number: you get 3.. thats why your answer is 3!

#Logic

Easy Math Editor

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`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
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Comments

$\begin{aligned} F &= \dfrac{2x+9-3}{2} - x \\ &= \dfrac{2x+6}{2} -x\\ &= x+3 -x \\ &= \boxed{3} \\ \end{aligned}$

Munem Shahriar - 3 years, 5 months ago

DYLAN MARSHALL - 3 years, 4 months ago

A Former Brilliant Member - 3 years, 4 months ago

Why

DYLAN MARSHALL - 3 years, 3 months ago

@DYLAN MARSHALL, hey about the project, can you send me url of image of the eccentric rotor? I want to see what you mean... just so you know, it's me. elmo.

Harry James Granger - 3 years, 1 month ago

@DYLAN MARSHALL, aka "Algebra whiz kid", How is the algebra going? Try my problem "https://brilliant.org/problems/this-is-what-i-had-for-hw/". It's HLS (Harvard Law School) Homework :)

A Former Brilliant Member - 3 years, 5 months ago

Weird person wasting my time

DYLAN MARSHALL - 3 years, 5 months ago

Meanie :(

A Former Brilliant Member - 3 years, 5 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$