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As a∈(0,1), RHS is real, positive and >2. But, LHS will be negative or 1 or non real. So, a∈(0,1) won't satisfy. Similar proof is also valid for a∈(−1,0). Hope it helps. :)
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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Yes, a=2 is only solution to above equation.
As above equation is valid for all x∈R, so it should also be valid for x=0. Putting x=0
cosa(0)=acosa0−1
1=a−1
a=2
As only one value of a comes out in solution, only one exists. Hope it helps. :)
@Zakir Husain
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Clever solution. :)
But if a∈(0,1) then multiple value of 1a are there (not considering principle values)
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Let a∈(0,1), then
1=a.1a−1 2=a.1a
1a=a2
As a∈(0,1), RHS is real, positive and >2. But, LHS will be negative or 1 or non real. So, a∈(0,1) won't satisfy. Similar proof is also valid for a∈(−1,0). Hope it helps. :)
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a∈C−R 1a will have ∞ values.
But ifFor example : (1)i=(ein2π)i=e−n2π,n∈Z (Not considering principle values)
Very cool. The double angle formula cannot be generalized. :)
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