Find A(XYTS)

PQRS is a rectangle and XYTS is a square. Length and breadth of the rectangle is 18cm and 12cm respectively. Find the area of XYTS.

I need help to solve this problem. I do not know the right answer. You can post the solution in the comments section.

Easy Math Editor

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Comments

Assume the side of the square to be $x.$

Then $PX$ = $18-x$ , $XY$ = $x$ , $PS$ = $18$ and $SR$ = $12.$

$\Delta PXY \sim \Delta PSR.$

=> $\frac{PX}{PS} = \frac{XY}{SR}$ => $\frac{18-x}{18} = \frac{x}{12}$ . => $x = 7.2$ => $x^{2} = 51.84$

Vishwash Kumar ΓΞΩ - 4 years, 2 months ago

Thanks a lot! :)

By the way, have you deactivated your slack account? I tried to reach you.

Ojasee Duble - 4 years, 2 months ago

Nah!! I will talk with you on 10th of the month. The owner is busy in exam, and I am out here.

Vishwash Kumar ΓΞΩ - 4 years, 2 months ago

@Vishwash Kumar Γξω – Okay

Ojasee Duble - 4 years, 2 months ago

@Ojasee Duble – Now come. We all are active on the team.

Vishwash Kumar ΓΞΩ - 4 years, 2 months ago

7.2 * 7.2 = 51.84

how did you get 50.44?

Ojasee Duble - 4 years, 2 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$