Que: Prove that sin^4 A - sin^2 A cos^2 A +cos^4 A + 3 sin^2 A cos^2 A - (sin^2 A + cos^2 A) + sin^3 A cosec^2 A = sin A. Student: Multiply R.H.S. & L.H.S. by 0 i.e. 0=0. Teacher gave marks: 10/10 * 0 = 0. For you: Can you find out the mathematical flaw in the answer given by the student and the marks given by the teacher which have given us misleading results? NOTE: We often multiply both sides by a rational no. in such questions but if we do that with 0 it becomes misleading. What's the reason?
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I think the reason why multiplying by 0 is misleading is that you cannot go back, i.e. dividing by 0 is not allowed. That follows the same concept when squaring a number. For example, given a negative number, say −a for some positive real number a2. If you square it, it would become a but you cannot say that getting the square root of a2 will lead you to a=−a. I will post later for the proof and for those who cannot understand, it says: sin4A−sin2Acos2A+cos4A+3sin2Acos2A−(sin2A+cos2A)+sin3Acsc2A=sinA Hint: Sum of Two Squares and Pythagorean Theorem P.S. I thought that student was smart but then I realized that the teacher was smarter. :P
sin4A−sin2Acos2A+cos4A+3sin2Acos2A−(sin2A+cos2A)+sin3Acsc2A=sinA (sin2A)2+(cos2A)2+2sin2Acos2A−1+sin3Acsc2A=sinA (sin2A+cos2A)2−1+sin3Acsc2A=sinA sin3Acsc2A=sinA sin3A∗sin2A1=sinA sinA=sinA
But 0 is not -ve. Then how can you apply the concept of squaring to this problem.