Find out mathematical flaw...

Que: Prove that sin^4 A - sin^2 A cos^2 A +cos^4 A + 3 sin^2 A cos^2 A - (sin^2 A + cos^2 A) + sin^3 A cosec^2 A = sin A. Student: Multiply R.H.S. & L.H.S. by 0 i.e. 0=0. Teacher gave marks: 10/10 * 0 = 0. For you: Can you find out the mathematical flaw in the answer given by the student and the marks given by the teacher which have given us misleading results? NOTE: We often multiply both sides by a rational no. in such questions but if we do that with 0 it becomes misleading. What's the reason?

#Geometry

Note by Sudo Jarvis
6 years, 6 months ago

No vote yet
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Comments

I think the reason why multiplying by 00 is misleading is that you cannot go back, i.e. dividing by 00 is not allowed. That follows the same concept when squaring a number. For example, given a negative number, say a-a for some positive real number a2a^2. If you square it, it would become aa but you cannot say that getting the square root of a2a^2 will lead you to a=aa=-a. I will post later for the proof and for those who cannot understand, it says: sin4Asin2Acos2A+cos4A+3sin2Acos2A(sin2A+cos2A)+sin3Acsc2A=sinA\sin^4 A - \sin^2 A \cos^2 A +\cos^4 A + 3 \sin^2 A \cos^2 A - (\sin^2 A + \cos^2 A) + \sin^3 A \csc^2 A = \sin A Hint: Sum of Two Squares and Pythagorean Theorem P.S. I thought that student was smart but then I realized that the teacher was smarter. :P

Marc Vince Casimiro - 6 years, 6 months ago

sin4Asin2Acos2A+cos4A+3sin2Acos2A(sin2A+cos2A)+sin3Acsc2A=sinA\sin^4 A - \sin^2 A \cos^2 A +\cos^4 A + 3 \sin^2 A \cos^2 A - (\sin^2 A + \cos^2 A) + \sin^3 A \csc^2 A = \sin A (sin2A)2+(cos2A)2+2sin2Acos2A1+sin3Acsc2A=sinA(\sin^2A)^2+(\cos^2A)^2+ 2 \sin^2 A \cos^2 A - 1 + \sin^3 A \csc^2 A=\sin A (sin2A+cos2A)21+sin3Acsc2A=sinA(\sin^2A+cos^2A)^2-1+\sin^3 A \csc^2 A=\sin A sin3Acsc2A=sinA\sin^3A\csc^2A=\sin A sin3A1sin2A=sinA\sin^3A*\frac{1}{\sin^2A}=\sin A sinA=sinA\sin A=\sin A

Marc Vince Casimiro - 6 years, 6 months ago

But 0 is not -ve. Then how can you apply the concept of squaring to this problem.

Sudo Jarvis - 6 years, 5 months ago
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