Food for thought: Solve this Physics problem

THINK:....a bar magnet is dropped without any initial velocity in a very long(but not considerable to earth's radius) hollow copper tube which is fixed to the ground of earth..the bar magnet is falling freely under gravity .......now my question:::::Can the accelleration of the bar magnet be zero...??............ think logically to crack it.....happy problem solving....thanks in advance for those who join this.....:)

Note by Sayan Chaudhuri
8 years ago

No vote yet
8 votes

  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

Yeah, it can be zero. By lenz law an upward force would act to oppose the change in magnetic field. As the speed of bar magnet increases, the change in magnetic field would increase and so does the force. A time would come when the upward force would balance downward force of gravity and bar magnet would fall with terminal velocity. Am I correct? Can someone help me finding the relation between upward force and rate of change in magnetic field?

Thanks for the question :)

Lokesh Sharma - 8 years ago

Log in to reply

you are exactly right in your description ......and you could also consider the matter of eddy current for this description.....then you deciphered the problem....:)

Sayan Chaudhuri - 8 years ago

Log in to reply

I now recall what happens exactly. The changing magnetic field produces eddy currents in the tube. The eddy current constitutes a magnetic dipole which repels the bar magnet. Right?

Lokesh Sharma - 8 years ago

Log in to reply

@Lokesh Sharma yea...right...!!

Sayan Chaudhuri - 8 years ago

good job! ;D

Thomas Luo - 8 years ago
×

Problem Loading...

Note Loading...

Set Loading...