From the AQA GCSE exam today.

So in the last question, after using a couple of rules I know about triangles, I worked out that two triangles were similar but had different side lengths. The East side of the first triangle was X but equaled 1.2 on the other, the south side of the fist triangle was lenghth 4.8 and X on the other. I was wondering, was the way to work it out, to do X/4.8 = 1.2/X which works out to be X²=5.76 so X=2.4? I'm asking because none of my mates got it so i have nobody to discuss with :/

#Algebra

Easy Math Editor

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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$