Functional Equation

Find all functions, f:RR,f : \mathbb{R} \rightarrow \mathbb{R}, such that

f(x+y)2f(xy)+f(x)2f(y)=y2.f(x+y) - 2f(x-y) + f(x) - 2f(y) = y-2.

#FunctionalEquations #VictorLoh

Note by Victor Loh
6 years, 10 months ago

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Comments

Let P(x,y)P(x,y) be the statement f(x+y)2f(xy)+f(x)2f(y)=y2f(x+y)-2f(x-y)+f(x)-2f(y)=y-2.

P(0,0)    f(0)=1P(0,0)\implies f(0)=1

P(x,x)    f(2x)=f(x)+xP(x,x)\implies f(2x)=f(x)+x

P(x,-x)\implies f(x)+2f(-x)=3-x\stackrel{x\to -x}\implies f(-x)+2f(x)=3+x

    f(x)+f(x)=2\implies f(x)+f(-x)=2

The last one was got by adding the 2 previous equations.

(2f(x))+2f(x)=3+x    f(x)=x+1(2-f(x))+2f(x)=3+x\implies f(x)=x+1

Thus f(x)=x+1f(x)=x+1 is the only possible solution. After checking it we see it works.\square

mathh mathh - 6 years, 10 months ago
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