There are two cups of water, which are both half-full. Then:
half full = half space
Multiply 2 both sides:
full = space
Which means everything can turn into nothing! Can you find the mistake?
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The half full=half space , is an abstraction of the quantity of the water(Volume) in the cup, hence at the end of the argument, essentially what you are saying is that the volume of a cup filled with water= to the value of the empty cup!, which is indeed true!. The only flaw is that you take into account the mathematical statement of full=space, which is a result of abstraction created by the 1st statement "There are two cups of water, which are both half-full" . The ' half full = half space " only makes sense if you are talking of the quantity, a meaning which is implied (not explicitly stated) AND THEN when you perform normal arithmetic you only take into account the mathematical statement not with respect to the initial context.
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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
The half full=half space , is an abstraction of the quantity of the water(Volume) in the cup, hence at the end of the argument, essentially what you are saying is that the volume of a cup filled with water= to the value of the empty cup!, which is indeed true!. The only flaw is that you take into account the mathematical statement of full=space, which is a result of abstraction created by the 1st statement "There are two cups of water, which are both half-full" . The ' half full = half space " only makes sense if you are talking of the quantity, a meaning which is implied (not explicitly stated) AND THEN when you perform normal arithmetic you only take into account the mathematical statement not with respect to the initial context.
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Ya that's right