Futoshiki problem 6 ?p=6

Answer say it needs only two number to have a unique solution. But here is an example where you start with two number, but the third can be defining different possible solution. 2 is not enough for unique solution it appears to me.

Please let me know if there's something i'm missing or if the solution provided is to be corrected. Thank you very much

Easy Math Editor

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`2 \times 3`	$2 \times 3$
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Comments

Hi, I believe you're referring to this problem.

the question reads:

What's the minimum number of digits that must be filled in before the puzzle can have a unique solution?

not

What's the minimum number of digits that must be filled in before the puzzle must have a unique solution?

In the future, if you have concerns about a problem's wording/clarity/etc., you can report the problem. See how here.

Brilliant Mathematics Staff - 3 months, 3 weeks ago

The correction says: 2 placements are enough, so long as they are different numbers (and are on different rows and columns).

The answer is 2? Or the answer is 2.. so long, and? If the answer is 2 so long, and.. those conditions should be told before and not after.

Daniel Assayag - 3 months, 2 weeks ago

The problem statement didn't state that you must fill in the same digit. So you're free to use distinct digits.

Brilliant Mathematics Staff - 3 months, 2 weeks ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$