Generalizing Common Difference

Here is a generalized formula to find the common difference. This is useful because it saves time in solving various problems.

Given an AP for which you don't know anything except that it's mthm_{th} term is pp and it's nthn_{th} term is qq. Then it's common difference is pqmn\frac{p-q}{m-n}.

Proof: Let aa be the initial term of the AP and dd be it's common difference. Then,

a+(m1)d=pa+(m-1)d=p

a+(n1)d=qa+(n-1)d=q

Subtracting our second equation from our first equation

a+(m1)da(n1)d=pq\cancel{a}+(m-1)d-\cancel{a}-(n-1)d=p-q

(m1n+1)d=pq(m\cancel{-1}-n\cancel{+1})d=p-q

d=pqmn\boxed{d=\frac{p-q}{m-n}}

#Algebra

Note by Zakir Husain
1 year ago

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