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  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

the answer is 3π/16

ANSHUL CHAUHAN - 8 years, 2 months ago

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4a1 + 4π(1/4)^2 - 4a2 = π(1)^2

ANSHUL CHAUHAN - 8 years, 2 months ago

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4a1+4π(1/2)24a2=π(1)24a_1+4π(1/2)^2 - 4a_2 = π(1)^2, implies a1a2=0a_1 - a_2 = 0

Adam Silvernail - 8 years, 2 months ago

0

Dharmik Panchal - 8 years, 2 months ago

Everyone has assumed that a1 and area of other "similar looking" sectors are equal, so that 4a1 is their total area. Similar assumption have been made for a2 also. But one needs to prove these assumptions.

Shubham Srivastava - 8 years, 2 months ago

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Here is the another method. Though the answer is same but the reasoning involved in this method is such that one doesn't require the above stated two assumptions, so there is no need to prove the assumptions.AreaOfSectorSOQ=90360πr2 Area Of Sector SOQ = \frac {90}{360} \pi r^2 AreaOfSemicircleSTO=12π(r2)2=AreaOfSemicircleQTOArea Of Semicircle STO = \frac {1}{2} \pi (\frac {r}{2})^2 = Area Of Semicircle QTO SectorSOQ=a1+SemicircleSTO+SemicircleQTOa2Sector SOQ = a_1 + Semicircle STO + Semicircle QTO - a_2 14πr2=a1a2+2×(12πr24)\frac {1}{4} \pi r^2 = a_1 - a_2 + 2 \times (\frac {1}{2} \pi \frac {r^2}{4}) a1a2=14πr214πr2=0a_1 - a_2 = \frac {1}{4} \pi r^2 - \frac {1}{4} \pi r^2 = 0

Shubham Srivastava - 8 years, 2 months ago
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