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Everyone has assumed that a1 and area of other "similar looking" sectors are equal, so that 4a1 is their total area.
Similar assumption have been made for a2 also. But one needs to prove these assumptions.
Here is the another method. Though the answer is same but the reasoning involved in this method is such that one doesn't require the above stated two assumptions, so there is no need to prove the assumptions.AreaOfSectorSOQ=36090πr2AreaOfSemicircleSTO=21π(2r)2=AreaOfSemicircleQTOSectorSOQ=a1+SemicircleSTO+SemicircleQTO−a241πr2=a1−a2+2×(21π4r2)a1−a2=41πr2−41πr2=0
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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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2^{34}
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the answer is 3π/16
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4a1 + 4π(1/4)^2 - 4a2 = π(1)^2
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4a1+4π(1/2)2−4a2=π(1)2, implies a1−a2=0
0
Everyone has assumed that a1 and area of other "similar looking" sectors are equal, so that 4a1 is their total area. Similar assumption have been made for a2 also. But one needs to prove these assumptions.
Log in to reply
Here is the another method. Though the answer is same but the reasoning involved in this method is such that one doesn't require the above stated two assumptions, so there is no need to prove the assumptions.AreaOfSectorSOQ=36090πr2 AreaOfSemicircleSTO=21π(2r)2=AreaOfSemicircleQTO SectorSOQ=a1+SemicircleSTO+SemicircleQTO−a2 41πr2=a1−a2+2×(21π4r2) a1−a2=41πr2−41πr2=0