Got some ee?

We all know by now one of these definition's of ee: e=limn(1+1n)n=n=01n!e=\lim_{n\to\infty}\left(1+\frac{1}{n}\right)^n = \sum_{n=0}^\infty \frac{1}{n!} But of course, these aren't the only ways to express it. This discussion is about sharing our favorite definitions of ee and why we think they're interesting.

#Calculus

Note by William Crabbe
3 years ago

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Comments

e=limn01+nne=\lim_{n\to0}\sqrt[n]{1+n} This version is simply an application of limnf(n)=limn0f(1/n)\lim_{n\to\infty}f(n)=\lim_{n\to0}f(1/n), but it's probably my favorite one to look at:


e=x:ddxxx=0e=x:\frac{d}{dx}\sqrt[x]{x}=0 From Wikipedia: "This maximum occurs precisely at x = e. For proof, the inequality eyy+1e^{y}\geq y+1, from above, evaluated at y=(xe)/ey=(x-e)/e and simplifying gives ex/exe^{x/e}\geq x. So e1/ex1/x e^{1/e}\geq x^{1/x} for all positive x.

William Crabbe - 3 years ago

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so what are you trying to say

Nahom Assefa - 2 years, 11 months ago
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