Gravitational energy to Spring energy

X has a mass of 55 kg and hangs from a rope. As a result of this, the rope stretches by 0.6 m. Calculate the energy stored in the rope as a result of stretching.

Solution:

F = kx and E = 0.5x^2. Using this fetches the answer as 161.5

However, the change in potential energy (calculated using mgh ) of X is exactly twice of this energy stored. Is there a relationship between the two?. What is the explanation?

#Mechanics

Easy Math Editor

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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$