Consider the following system of equations:
a=(c15b+5d−1)0.5,b=(d15c+5a−1)0.5
c=(a15d+5b−1)0.5,d=(b15a+5c−1)0.5
Evaluate the value(s) of the expression
a+b+c+d+ab+ac+ad+bc+bd+cd.abc+abd+acd+bcd+4abcd
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Hint: if we let a=b=c=d, we yield a=7, and the desired expression has only one possible value: 14.
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You can't just assume that the expression is constant ∀a,b,c,d∈R; you'll have to prove it.