A man is running up an incline planr maaking an angle θ with horizontal with a speed u .Rain drops falling at an angle α with the vertical appear to the man as if they are falling at an angle of 45o with the horizontal. The speed of rain drops is
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While talking about the rain, you took its direction in the south west direction. What prompted you to do that?? Why didn't you take it in the south-east direction?? In that case the x-component of relative velocity will be
ucos(theta)-vsin(alpha) and not ucos(theta)+vsin(alpha) as in this case...
Both are equivalent. Just interchange α in my equation with −α to get to the result that you have mentioned. This disparity arises since I am measuring the angle in the clockwise direction, while you are measuring it in the anticlockwise direction.
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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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Take relative velocity along x and y axes and equate magnitude
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While talking about the rain, you took its direction in the south west direction. What prompted you to do that?? Why didn't you take it in the south-east direction?? In that case the x-component of relative velocity will be
ucos(theta)-vsin(alpha) and not ucos(theta)+vsin(alpha) as in this case...
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Both are equivalent. Just interchange α in my equation with −α to get to the result that you have mentioned. This disparity arises since I am measuring the angle in the clockwise direction, while you are measuring it in the anticlockwise direction.
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@Raghav Vaidyanathan @Tanishq Varshney @Ronak Agarwal
v=usin(π/4−θ)csc(π/4−α)
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Can u explain in brief
Shouldn't be there plus sign in sin part
Yes i solved it . Any way thanx for helping .