Help identifying missing part of algebra education

I am unable to follow an explanation provided in 'Mathematical Fundamentals: The Quadratic Formula' and was wondering if anyone could point me in the right direction so that I can fill in the necessary gap(s) in my algebra education?

Problem referenced: https://brilliant.org/practice/quadratic-formula/?p=9

In the explanation provided to the above referenced problem I'm confounded straight out of the gate; I don't understand why you would/should 'multiply a by the denominator and numerator so that it has the same denominator as the term it is subtracting from' - I see that doing this makes both denominators the same, however don't understand why doing this is okay.

Any help greatly appreciated, Matthew

#Algebra

Note by Matt Lee
11 months, 2 weeks ago

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Comments

You're basically subtracting two fractions.

4523=4×32×55×3 \frac45 - \frac23 = \frac{4\times3 - 2\times5}{5\times3}

So b2a24ca=b2×a4c×a2a×a3=a×b2a×4c×aa×a2=a(b24c×a)a×a2=b24c×aa2 \dfrac{b^2}{a^2} - \dfrac{4c}a = \dfrac{b^2 \times a - 4c \times a^2}{a\times a^3} = \dfrac{a \times b^2 - a \times 4c \times a}{a \times a^2} = \dfrac{\cancel a( b^2 - 4c \times a)}{\cancel a \times a^2} = \dfrac{ b^2 - 4c \times a}{ a^2}

Pi Han Goh - 11 months, 2 weeks ago

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Thanks Pi! Very kind of you and just what I needed 🙏🏼

Matt Lee - 11 months, 1 week ago
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