Help in Solving Physics Differential equation.

Hello everyone!

I'm unable to solve this differential equation while solving a physics question. So please help me in solving this equation:

\[m\frac{dv}{dt}=mg -\lambda\frac{v}{x(x-d)}\] or

mvdvdx=mgλvx(xd).m\frac{vdv}{dx}=mg-\lambda \frac {v }{x(x-d)}.

UPDATEUPDATE:

HereHere II wantwant toto expressexpress eithereither

v=f(t)v=f(t)

or

v=f(x) v=f(x).

GivenGiven.

where all terms have the usual meaning:

'λ\lambda ' is constant.

vv is the velocity of the rod (variable)

mm is the mass of the rod (constant)

xx is the distance from a fixed point to the rod (variable)

tt is time (obviously a variable)

and dd is the intial distance (constant)

NoteNote:

This is a part of a question that I'm writing. I'm unable to proceed further because of this difficult differential equation.

Please help! Thanks.

UPDATE

Click here to get full Question Click Here.

#Calculus #Physics #ElectricityAndMagnetism #Mechanics #HelpMe!

Note by Deepanshu Gupta
6 years, 8 months ago

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1 vote

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Comments

In the first equation multiply both sides by differential dtdt.Also write v=dxdtv = \frac {dx}{dt}.

You should get : mdv=mgdtλdxx(xd)mdv = mgdt - \frac {\lambda dx}{x(x-d)}

You also need to know three initial conditions : Initial time which is 00,initial position and initial velocity.

Did I make a mistake in doing this?

Arif Ahmed - 6 years, 8 months ago

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Yes i did it in same way...!!

But I want to express velocity as either v=f(t)v=f(t) or v=f(x)v=f(x) so that further question is completed. Since Both time and distance are different. I mean to say if I want to calculate say velocity at the instant say at t=10 s then how could I know velocity at that instant since position is also unkown at that instant of Time. ?? and Also according to this question v=d(xd)dtv = \frac {d(x-d)}{dt}. which is also same thing as v=dxdtv = \frac {dx}{dt}.

Deepanshu Gupta - 6 years, 8 months ago

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I believe the differential equation is not meant to be solved by wolfram alpha itself.

Ronak Agarwal - 6 years, 8 months ago

@Ronak Agarwal @jatin yadav will you help ??

Deepanshu Gupta - 6 years, 8 months ago

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@Pranav Arora @Finn Hulse any Help??

Deepanshu Gupta - 6 years, 8 months ago

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I don't think I'll be of much help on the problem, but certainly the LaTeX needed editing. Is this the way you would like it to appear?

Finn Hulse - 6 years, 8 months ago

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@Finn Hulse Thanks,@Finn But how can I expressed v=f(x) v=f(x) or v=f(t)v=f(t).?? which is essential for this question. ( that is my Problem)

Deepanshu Gupta - 6 years, 8 months ago

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@Deepanshu Gupta I'm not sure I understand what you mean.

Finn Hulse - 6 years, 8 months ago

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@Finn Hulse Is it possible to express the velocity as an individual function ?? or we require Higher mathamatics??

Deepanshu Gupta - 6 years, 8 months ago

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@Deepanshu Gupta Are you asking if you can solve for vv? Because if you are, I think it would be very tricky.

Finn Hulse - 6 years, 8 months ago

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@Finn Hulse yes.. will you please give a try to it ? I make all possible attempt but not succesfull in it.

Deepanshu Gupta - 6 years, 8 months ago

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@Deepanshu Gupta Sure. Also, I've been to Jaipur! It's super awesome! :D

Finn Hulse - 6 years, 8 months ago

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@Finn Hulse wow.. !! A very warm welcome to you for coming in Jaipur..... In our Language we says:

"padharopadharo mharemhare deshdesh"

Well for what purpose you have been come here... is it Vacation's celebration or something else ?

Deepanshu Gupta - 6 years, 8 months ago

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@Deepanshu Gupta I took a trip around Rajasthan and also to Agra (for obvious reasons). I visited Delhi, Jaipur, Udaipur, Bundi, Chittogarth, Ranthambhore, and some other places. :D

Finn Hulse - 6 years, 8 months ago

@Calvin Lin sir @Michael Mendrin sir any help??

Deepanshu Gupta - 6 years, 8 months ago

Can you please post that whole physics question itself on which you are working.

Ronak Agarwal - 6 years, 8 months ago

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@Ronak Agarwal Ok Done it. You can check it Here.

Deepanshu Gupta - 6 years, 8 months ago

Hi Deepanshu please try this question. I think you will find this interesting.

satvik pandey - 6 years, 7 months ago

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@satvik pandey Done..!!

Deepanshu Gupta - 6 years, 7 months ago
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