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From a disc of mass 2kg and radius 4m a small disc of radius 1m with center OO^{\prime} is extracted .The new moment of inertia about an axis passing through O perpendicular to plane of disc is

#Mechanics

Note by Kyle Finch
6 years, 2 months ago

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Comments

Moment of Inertia of Initial disc about center = Moment of inertia about center of part that is removed+ moment of inertia about center of whatever is left

Raghav Vaidyanathan - 6 years, 2 months ago

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I missed the diagram. Plz see above

Kyle Finch - 6 years, 2 months ago

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I'm still not getting a diagram

Raghav Vaidyanathan - 6 years, 2 months ago

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@Raghav Vaidyanathan Now u may see

Kyle Finch - 6 years, 2 months ago

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@Kyle Finch What I said above still applies. The MOI of the whole disc is sum of the removed part and what's left.

Raghav Vaidyanathan - 6 years, 2 months ago

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@Raghav Vaidyanathan OK thanks , can u also tell me the solution to this dydx=x+x24y2\frac{dy}{dx}=\frac{x+\sqrt{x^2-4y}}{2}

Kyle Finch - 6 years, 2 months ago

The answer is 247/16 kgm^2

Kyle Finch - 6 years, 2 months ago
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