From a disc of mass 2kg and radius 4m a small disc of radius 1m with center O′ is extracted .The new moment of inertia about an axis passing through O perpendicular to plane of disc is
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Moment of Inertia of Initial disc about center = Moment of inertia about center of part that is removed+ moment of inertia about center of whatever is left
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2^{34}
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@Raghav Vaidyanathan @Ronak Agarwal @Jake Lai
Moment of Inertia of Initial disc about center = Moment of inertia about center of part that is removed+ moment of inertia about center of whatever is left
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I missed the diagram. Plz see above
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I'm still not getting a diagram
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dxdy=2x+x2−4y
OK thanks , can u also tell me the solution to thisThe answer is 247/16 kgm^2