Does (σ0(a)a)=0\binom{\sigma_0(a)} a=0(aσ0(a))=0 for n≥3n \ge 3n≥3 and nnn is a positive integer?
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Note by Gia Hoàng Phạm 2 years, 2 months ago
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When n≥3n \geq 3n≥3 it is true that σ0(n)≤n\sigma_0(n) \leq nσ0(n)≤n. And by definition, (uv)=0\binom{u}{v} = 0(vu)=0 where u<vu \lt vu<v. So it looks to me like the answer is yes.
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An interesting example solution. Personally, when I was a student, I didn’t really bother with math. This was not my core subject. Yes, and I just did not like it. I use site check this out. There you can buy assignment online, find essays or math examples. All my friend use or used this when want to time and get quality materials.
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I don't think brilliant.org members fit the profile of the type of people who would be interested in an academic cheating web site.
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
When n≥3 it is true that σ0(n)≤n. And by definition, (vu)=0 where u<v. So it looks to me like the answer is yes.
Absolutely correct, a cheating site cant be referred but a site like Student Life Saviour can be referred, as they never do assignments, rather their professionals give hints on how to do maths problem easily.
An interesting example solution. Personally, when I was a student, I didn’t really bother with math. This was not my core subject. Yes, and I just did not like it. I use site check this out. There you can buy assignment online, find essays or math examples. All my friend use or used this when want to time and get quality materials.
Log in to reply
I don't think brilliant.org members fit the profile of the type of people who would be interested in an academic cheating web site.