Help me with this!

The semicircle above has a radius of 7.

Find X.

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

Yes, it not possible to get the value of X. link

Elizabeth King - 2 years, 10 months ago

Not enough info. I would expect to be given the length of the other horizontal. Then it would be easy.

Jeremy Galvagni - 2 years, 10 months ago

BTW, is it possible?

Interliser 727 - 2 years, 10 months ago

Yes it is possible to calculate but check whether all the information is required or not . I think some information is missing .

Ram Mohith - 2 years, 10 months ago

I don't really know, but it only gave me the radius.I'll check again later

Interliser 727 - 2 years, 10 months ago

@Interliser 727 – If we know the length of the chord we can easily find the answer.

Ram Mohith - 2 years, 10 months ago

@Ram Mohith – 2nd cord?

Interliser 727 - 2 years, 10 months ago

@Interliser 727 – Yes the chord above the diameter

Ram Mohith - 2 years, 10 months ago

@Ram Mohith – It says the second cord is the bottom of an imaginary square and the surface area of two connected in form of up and down cube created with the imaginary square is 50.

Interliser 727 - 2 years, 10 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$