Here's another problem that I actually got correct, but just to compare my reasoning with the "view result" I clicked there and the explanation is so weird. Here's the problem and it's solution follows:
Two people, Alice and Bill, each roll a fair 20-sided die. What is the probability that Alice's roll is higher than Bill's roll?
Solution: The probability that they roll the same number is so the probability that they do not roll the same number is By symmetry, if they do not roll the same number, each of Alice and Bill is equally likely to have rolled the higher number. The answer is thus
What I was thinking: Bill either rolls 1, or 2, or,...., or 19. Then Alice beats Bill if she gets any of the next 19 numbers, or the next 18 numbers, or,....,or the last number 20. Then using a formula, Alice can beat Bill in ways which give same result.
My question: Alice and Bill having equally likely chances to roll higher means that we're like flipping a coin? How will I be able to spot this strategy in other problems? If I were to write this in words, does this mean that we are calculating P(Alice wins) = P(They do not roll same and Bill loses) = P(They do not roll same)P(Bill loses) = P(They do not roll same and Alice wins)?
Reflections: I guess I do understand the technique. My previous paragraph kind of Illustrates what is meant by "symmetry" and equal likelihood. So I'm making this note more like a reflexion kind of thing than a question.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
I am also confused by this problem. Can somebody explain to me how the probability they roll the same is 1/20 shouldn't it be 1/20 * 1/20
Log in to reply
The number of eyes of the first roll doesn't really matter. Let's say Alice rolls a 2, the chance that Bill rolls a 2 is 1/20 (But Alice can also roll a 15 for example, than Bill has to roll a 15 as well, which has a probability of 1/20).
Log in to reply
Thank you man for the explaination