Help please

Consider a sequence $a_{n} ; n \in N$ with $a_{0}=a_{1}=a_{2}=a_{3} =1$ and $a_{n} a_{n-4} = a_{n-1}a_{n-3} +a^{2}_{n-2}$ for all n>3.

Prove that all the terms of this sequence are integers.

#Algebra

Easy Math Editor

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Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

@Sharky Kesa

Harsh Shrivastava - 4 years, 5 months ago

What have you tried? Where are you stuck?

Calvin Lin Staff - 4 years, 5 months ago

I too need help in this question.

Aaron Jerry Ninan - 4 years, 5 months ago

use P.M.I , it is easy , this way .

A Former Brilliant Member - 4 years, 5 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$