Let aaa and bbb are two numbers such that a=b=2a = b = 2a=b=2.
Therefore a2=aba^2 = aba2=ab [multiplying aaa on both sides.]
a2−b2=ab−b2a^2 - b^2 = ab - b^2a2−b2=ab−b2 [subtracting b2b^2b2 on both sides.]
(a+b)(a−b)=b(a−b)(a + b)(a - b) = b(a-b)(a+b)(a−b)=b(a−b)
(a+b)=b(a+b) = b(a+b)=b
Now substituting the values of aaa and bbb , we get 2+2=22+2 = 22+2=2
Therefore 4=24 = 24=2 ?
Note by Rama Devi 5 years, 10 months ago
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you cannot cancel (a-b) on both sides because (a-b) =0 and division by 0 is not defined!
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good observation
You are only 13 and you are level 5 in all subjects .Cool! Do you sit whole day at brilliant or you attempt every question correctly?
You cannot cancel out (a-b). Think why?
Because a - b is 0
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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to ensure proper formatting.2 \times 3
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a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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you cannot cancel (a-b) on both sides because (a-b) =0 and division by 0 is not defined!
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good observation
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You are only 13 and you are level 5 in all subjects .Cool! Do you sit whole day at brilliant or you attempt every question correctly?
You cannot cancel out (a-b). Think why?
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Because a - b is 0