It is easy to identify that all the numbers are beginning with 3 \(\therefore\) all that you have to do is factorize:
\large \color{#20A900} (3^{23} - 3^{22})(3^{24} - 3^{23})(3^{25} - 3^{24}) \\ \large \color{#20A900} \implies 3^{22}(3 -1) \times 3^{23}(3 -1) \times 3^{24}(3 -1) & \small \color{#D61F06} \text{Note: all of them relate to} 3 - 1 \implies 2 \text{which correspnds to the question} \\ & \large \color{#69047E} \implies 3^{22}(2) \times 3^{23}(2) \times 3^{24}(2) \\ \large \color{#69047E} = 2^3 \times 3^{22+23+24} \\ \large \color{#EC7300} = 2^3 \times 3^{69}
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(323−322)(324−323)(325−324)⟹322(3−1)×323(3−1)×324(3−1)Note: all of them relate to3−1⟹2which correspnds to the question⟹322(2)×323(2)×324(2)=23×322+23+24=23×369
You cannot have & in the codes, unless you use \begin{align} \end{align}, \begin{cases} \end{cases}, \begin{array} \end{array}, \begin{matrix} \end{matrix}, etc.
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Thanks