Help with a cryptogram problem

I need help understanding a problem's solution. Let's say I am given the cryptogram XX + YY + ZZ = XYZ. I know what the variables are (X=1, Y=9, Z=8), but how did those variables equal those amounts? This is the last problem in the first module of the Mathematical Fundementals course, but the explanation they gave me made no sense to me for some reason. Can someone help me explain the solution to this problem in a simpler way?

#Algebra

Note by Dimitry Vartan
2 years, 5 months ago

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Comments

I believed that you're referring to this problem.

Here's an alternative solution:

The largest possible value of the sum of XX,YY,ZZXX, YY, ZZ is 99+88+77=26499 + 88 + 77 = 264. And since the final sum is a 3-digit number, then X=1X = 1 or X=2X = 2 only.

Suppose X=2X = 2, the equation simplifies to 22+YY+ZZ=2YZ22 + YY + ZZ = 2YZ. Converting YY,ZZ,2YZYY, ZZ, 2YZ into proper algebraic expressions gives 10Y+Y,10Z+Z,200+10Y+Z10Y + Y, 10Z + Z, 200 + 10Y + Z.

Substituting them gives 22+(10Y+Y)+(10Z+Z)=200+10Y+Z22 + (10Y + Y) + (10Z + Z) = 200 + 10Y + Z . Simplifies it gives Y+10Z=178Y + 10Z = 178 . Since YY and ZZ are distinct single digits, then there's no solution.

Hence, X=1X = 1 only. The equation simplifies to 11+YY+ZZ=1YZ11 + YY + ZZ = 1YZ. Converting YY,ZZ,2YZYY, ZZ, 2YZ into proper algebraic expressions gives 10Y+Y,10Z+Z,100+10Y+Z10Y + Y, 10Z + Z, 100 + 10Y + Z.

Substituting them gives 11+(10Y+Y)+(10Z+Z)=100+10Y+Z11 + (10Y + Y) + (10Z + Z) = 100 + 10Y + Z . Simplifies it gives Y+10Z=89Y + 10Z = 89 . Since YY and ZZ are distinct single digits, then Y=9,Z=8Y = 9, Z = 8.

And we're done!

Pi Han Goh - 2 years, 4 months ago
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