Help with Gibbs' Free Energy!

There's an equation that states ΔG = - RT ln K, where ΔG is the Gibbs' free energy at standard conditions, R is the universal gas constant, T is the temperature, and K is the equilibrium constant.

Is K = Kc (in terms of concentrations) or K = Kp (in terms of partial pressures)?

According to this equation it seems to be dimensionless!

#Chemistry

Easy Math Editor

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Comments

It is $K_{c}$ i.e. in terms of concentration.

Akshay Yadav - 5 years, 4 months ago

Both Kp nd Kc I guess, because any sort of equilibrium is considered in the equilibrium, it's just a particular value of the reaction quotient attained at equilibrium.

Dipanjan Chowdhury - 5 years, 2 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$