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If you have 2 vectors of magnitudes a and b with an angle θ between them, then their resultant has a magnitude of a2+b2+2ab×cosθ . (Try to prove this using the triangle law of vector addition).
Thus in your 1st case, the resultant is v2+v2+2v2cosθ=2v2(1+cosθ)=v2+2cosθ=v4cos22θ=2v×cos2θ .....
we used the result " cos(2θ)=21+cosθ ", which is easy to prove using cosθ=cos(2θ+2θ)=cos2(2θ)−sin2(2θ)=2cos2(2θ)−1
In the seconds case, only difference occurring is θ becomes 180∘−θ hence in the half angle thing, it will become 90∘−cos(2θ) and that will become sin(2θ) , giving the final result as 2u×sin(2θ)
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
If you have 2 vectors of magnitudes a and b with an angle θ between them, then their resultant has a magnitude of a2+b2+2ab×cosθ . (Try to prove this using the triangle law of vector addition).
Thus in your 1st case, the resultant is v2+v2+2v2cosθ=2v2(1+cosθ)=v2+2cosθ=v4cos22θ=2v×cos2θ .....
we used the result " cos(2θ)=21+cosθ ", which is easy to prove using cosθ=cos(2θ+2θ)=cos2(2θ)−sin2(2θ)=2cos2(2θ)−1
In the seconds case, only difference occurring is θ becomes 180∘−θ hence in the half angle thing, it will become 90∘−cos(2θ) and that will become sin(2θ) , giving the final result as
2u×sin(2θ)
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oh thanks for your contribution aditya!
go for vector addition
S=\sqrt { v^{ 2 }+v^{ 2 }+2v.v.\cos \theta } =\sqrt { 2v^{ 2 }+2v^{ 2 }\cos \theta } =\sqrt { 2v^{ 2 }(1+\cos \theta ) } =\sqrt { 2v^{ 2 }(2\cos ^{ 2 } \theta /2) } ............................changing1+\cos \theta to half angle form =\sqrt { 4v^{ 2 }\cos ^{ 2 } \theta /2 } =2v\cos \theta /2
change this to text. And do same for difference.
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ok i'll try it. thanks @Rajeev sharma