This discussion board is a place to discuss our Daily Challenges and the math and science
related to those challenges. Explanations are more than just a solution — they should
explain the steps and thinking strategies that you used to obtain the solution. Comments
should further the discussion of math and science.
When posting on Brilliant:
Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.
Markdown
Appears as
*italics* or _italics_
italics
**bold** or __bold__
bold
- bulleted - list
bulleted
list
1. numbered 2. list
numbered
list
Note: you must add a full line of space before and after lists for them to show up correctly
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
@Zakir Husain
@Mahdi Raza, @Vinayak Srivastava
I have no idea, @Syed Hamza Khalid.
@Zakir Husain, can you help him out?
Log in to reply
I'm trying right now!!!
An approach could be to make a quadratic in n and equating the discriminant greater than 0. Maybe... but I don't see whether it's truly possible
Log in to reply
Doesn't lead to anything sadly
Log in to reply
Yes it doesn't
The problem seems interesting, but way more difficult than it looks! I'll try and tell if I am able to find something(very less probability though).
Log in to reply
Not surprisingly, I could not find a good method. Sorry!
All I can figure out is that ab=0\1.
Meaning 0 or 1.
Log in to reply
Not really though.
Such a condition is satisfied by the integers:
n=9,a=7,b=13 and n=16,a=13,b=21
Log in to reply
Well - this is out of my league...
Log in to reply
This is a solution using the Euclidean algorithm
Log in to reply
How you can say that n≥a
Log in to reply