This isn't my homework. It's a math problem I picked up while reading a book to promote clearer thinking. I know the answers are 56 and 42, but I'm wondering about how to restate the second equation in the system with this problem: 'the ages of a man and his wife together are 98. He is twice as old as she was when he was the age she is today. What are their ages?'
Obviously, the first equation would be . Does one state the second equation as ? But then wouldn't that add another variable?
Thank you.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
I suppose you meant to say "He is as old as 's'he was ...."
You can take the variables as the current age of the wife, yand the difference between their ages, a
Then the man's current age is y+a
When the man was as old as his wife is today, he was y years old and his wife was y−a
We are given that y+a=2(y−a)
Hence the two equations.
Log in to reply
That still creates a third equation, because a is not known. Thank you! :)
Log in to reply
Yes, but that will lead to a being the second variable and not x One equation will bey+a=2(y−1) The second is y+(y+a)=98
Log in to reply
?? Wouldn't the second EQ just be x=2y?