How Slow Does Harmonic Series Grow?

Ok so we know that Harmonic series Hn=k=1n1k\displaystyle H_n = \sum_{k=1}^n\dfrac1k diverges. And by integral test, we can see that ln(n+1)=1n+1dxx   <   Hn   <   1+1ndxx=1+ln(n)\ln(n+1) = \int_{1}^{n+1} \dfrac{\mathrm d x}x ~~~<~~~ H_n ~~~<~~~ 1+\int_1^n\dfrac{\mathrm d x}x = 1+\ln(n)

Saying we use a computer that add a million of terms per second, and we have it doing that for a million years.

That would be n=602243651012<3.21019n = 60^2\cdot24\cdot365\cdot10^{12} < 3.2\cdot10^{19}

Hence ln(n)<ln(3.2)+19ln(10)<45\ln(n) < \ln(3.2) + 19\ln(10) < 45. Since Hn<1+ln(n)H_n < 1 + \ln(n), that means after million years of addition, HnH_n still hasn't reached 4646. Wow!

Isn't it amazing that HnH_n grows extremely slow, yet it diverges?

#Calculus #HarmonicSeries #Harmonic #Growth

Note by Micah Wood
5 years, 6 months ago

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Comments

Somewhat relevant.

Pi Han Goh - 5 years, 6 months ago
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