How to solve this?

I was practising algebra when I came across this question. I don't really have this concepts in my school so I would like to know how to do that. Also I tried pressing solution button but it's not working.

#A #E #B

Easy Math Editor

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Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

Think logically: The goal is to express 216 as the product of a power of two and a power of three. To do so, we must split 216 into its prime factors: $216 = 36 \cdot 6 = 6^3 = 3^3 \cdot 2^3$ . We see that $a=3$ and $b = 3$ , so $a+b$ is simply $6$ .

Lee Wall - 7 years, 3 months ago

A Former Brilliant Member - 7 years, 3 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$