Standard Minkowski space time Invariant definition tells us
\[d\phi^2 = c^2 dt^2 -\sum_{n} (dx^n)^2 \] \(d\phi=\textrm{Space time Invariant}\)
"n"refers to all possible spatial coordinatesProve that Space time Invariant remains constant in all frame of references
Let's take the simplified form(only taking the one spatial dimension) for a Frame of reference ϕ2=c2t2−x2
(Here c = speed of light and u =relative velocity between two reference frames )
For Another frame of Reference
Lorentz transform says t′=β(t−c2ux) (where β=1−c2u21 )
And x′=β(x−ut)
Now inserting these on that equation ϕ′2=c2t′2−x′2⟹ϕ′2=c2β2(t−c2ux)−β2(x−ut)2=c21−c2u21(t2−2c2uxt+c4u2x2)−1−c2u21(x2−2uxt+u2t2)
After simplifying
ϕ′2=c2t2−x2=ϕ2
Which means ϕ=ϕ′ or Space time Invariant as a constant.
But the in original equation It is stated as dϕ2+dx2+dy2+dz2+(icdt)2=0
So is it Reasonable to include all possible spatial dimensions in that Minkowski space time equation? (Shown in the first)
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Hi @Dwaipayan Shikari, I can't figure out what you mean by "is it reasonable to include all possible spatial dimensions in that Minkowski space time equation?" Can you say more specifically what your question is?
I have seen only dx,dy,dz spatial dimensions in minkowski space time equation along with time dimension.
It is true for 4d space . My question is , "Is it possible to add more spatial dimensions like dx,dy,dz ?"
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Hi @Dwaipayan Shikari, I can't figure out what you mean by "is it reasonable to include all possible spatial dimensions in that Minkowski space time equation?" Can you say more specifically what your question is?
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I have seen only dx,dy,dz spatial dimensions in minkowski space time equation along with time dimension. It is true for 4d space . My question is , "Is it possible to add more spatial dimensions like dx,dy,dz ?"