Extremely large summation

x=99y=88z=110g=999100e10(x3+y3×z3)n=1881n5100+g\sum_{x=99}^∞\sum_{y=88}^∞\sum_{z=110}^∞\sum_{g=999}^∞ 100\frac{e^{10}(x^{3}+y^{3} \times z^{3})}{\prod_{n=1881}^∞\frac{n^{5}}{100}+\sqrt{g}}

if the above equation is equal to ab\frac{a}{b} find a×ba \times b then minus that number by 1/2

i wont post solution until you do

#Calculus

Note by Garrett O’Brien
5 years, 2 months ago

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Comments

Brilliant staff please help him

Aman Rajput - 5 years, 2 months ago

Oh meee gord sooo deeffirricalt. Though honestly, this sum doesn't make any sense. One look and you'll know it doesn't even converge.

Julian Poon - 5 years, 2 months ago

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But converging isn't involved, and you'll see why

Garrett O’Brien - 5 years, 2 months ago

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Ok, I think you just have a misconception of how the summation works. Go look up on it to see how you can rephrase your question. I've also noticed you changed the question. It still doesn't converge.

Julian Poon - 5 years, 2 months ago

@Ark3 Graptor

Kindly refrain from using note titles like you did previously. These may provoke fights which are uncharacteristic to the Brilliant community.

Mehul Arora - 5 years, 2 months ago

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my bad i didnt mean it in a bad way

Garrett O’Brien - 5 years, 2 months ago
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