A gun fires bullets of each of ,mass 1gram with velocity of 10m/s by exerting a constant force of 5 g weight. then the number of bullets fired per second is- (g=10 m/s^2)
please me of this problem and let me know the answer in detail.
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We know that force = change in momentum/time. Now force is 50 N. Change in momentum is =
Number of bullets1gram(v-u)=10number of bullets. We assume bullet is first at rest and then it attains momentum. So 50 = 10*number of bullets/1 second. Thus we get 5 bullets per second
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
We know that force = change in momentum/time. Now force is 50 N. Change in momentum is = Number of bullets1gram(v-u)=10number of bullets. We assume bullet is first at rest and then it attains momentum. So 50 = 10*number of bullets/1 second. Thus we get 5 bullets per second