impossible

Find x?

1+x=x

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

The answer is $x \in C$ ,where C is the set of Complex numbers .

A Former Brilliant Member - 6 years, 2 months ago

I don't get which complex number will satisfy the above equation.

But I think the above equation is satisfied as $x\to\infty$ .

Prakhar Gupta - 6 years, 2 months ago

Enter an Complex number in place of x , 1=0 . The constant=constant equality still holds .

I think this kind of equality is used in solving questions based on Inequalities .

A Former Brilliant Member - 6 years, 2 months ago

I think it is indeterminate form since it will be in the form of $\dfrac{1}{0}$ .

Parag Zode - 6 years, 2 months ago

No solution because if you cancel out the 'x's you'll get 1=0 which is simply not possible.

Vasudev Chandna - 6 years, 1 month ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$