In a given triangle ABC, a=BC, b=AC, and c=AB where ABC are angle measurements of the triangle. Can you prove that the following inequality is true? Moreover, is there any maximum value of the fraction in the center of the inequality?

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

INDONESIA, makassar. abdui,karim

kayu kaou - 7 years, 6 months ago

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H=4

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6 box

kayu kaou - 7 years, 6 months ago

Determine the smallest integer that is divisible by 24 and has digit sum equal to 24.

kayu kaou - 7 years, 6 months ago

Since 24 = 8 * 3, the sum of the digits must be = 0 (mod 3), which is satisfied by the fact that the sum of the digits must be 24. Therefore, we ignore this condition, so now we need the smallest n = 0 (mod 8 ), whose sum of digits = 24. We clearly

kayu kaou - 7 years, 6 months ago

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kayu kaou - 7 years, 6 months ago

6v1 4v1 2v1 2v2 4v1 2v0

kayu kaou - 7 years, 6 months ago

6 1 _+ 6

4 1 __+ 5

2 1 _+ 3

2 2 __+ 4

4 1 __+ 5

2 0 __+ 20

kayu kaou - 7 years, 6 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$