Inclined Planes

Why normal force between blocks is always zero irrespective of theta?(Friction is absent everywhere). LaTeXLaTeX

Note by Om Tiwari
2 years, 10 months ago

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Comments

Suppose that the distance between the blocks remains zero, and that the acceleration of both blocks is the same. The normal force NN acts on the blocks equally and oppositely, per Newton's Third Law.

m1gsinθ+N=m1am2gsinθN=m2am_1 \, g \, sin \theta + N = m_1 \, a \\ m_2 \, g \, sin \theta - N = m_2 \, a

Adding both equations:

(m1+m2)gsinθ=(m1+m2)aa=gsinθ(m_1 + m_2) \, g \, sin \theta = (m_1 + m_2) \, a \\ a = g \, sin \theta

Plugging aa back into original equations:

m1gsinθ+N=m1gsinθ    N=0m2gsinθN=m2gsinθ    N=0m_1 \, g \, sin \theta + N = m_1 \, g \, sin \theta \, \implies N = 0 \\ m_2 \, g \, sin \theta - N = m_2 \, g \, sin \theta \, \implies N = 0

Steven Chase - 2 years, 10 months ago

@Rajdeep Dhingra @Steven Chase @Josh Silverman @Pranshu Gaba

Om Tiwari - 2 years, 10 months ago
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