Solving the last problem made you observe that the first 3 perfect numbers are of the .
Actually it was proved by Euclid that :
If ( is a prime the is perfect and every perfect number of this form.
Try to prove it in the comments box :)
You can also see that this implies all even perfect numbers are triangular numbers.
Also no odd perfect number has been found so far.
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Let 2k−1=Mp [short for Mersenne Prime].
The positive divisors of n=2k−1(2k−1) are 1, 2, 22, 23 ⋯ 2k−1 and Mp,2Mp,22Mp,23Mp,⋯2k−1Mp.
Let's add them all together.
We get σ(n)=2k−1+Mp×(2k−1)=(2k−1)(1+Mp)=(2k−1)×2k=2×2k−1(2k−1)=2n.
So, n is a perfect number by definition.
When I first found out about perfect numbers (I was 9), I strived to find a pattern between them. After 2 hours only I figured it out but then checked the Internet. Turns out it was discovered by Euclid over 2000 years ago. I still felt proud.
It was proven by Euler that every even perfect number must have this form.
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I think you're right ..but the general form was given by Euclid right??
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Yes, Euclid found out that 2p(p+1) was a perfect number for certain prime numbers p. He concluded that those prime numbers had to be of the form 2k−1. These primes are now called Mersenne Primes.
Euler later on proved that all even perfect numbers must have this form.
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