Inequality?

Let xx and yy be real number with xy1,xy \neq -1, and x7y+xy71+x5y5=5\displaystyle \frac{x^7y+xy^7}{1+x^5y^5} = 5 What is the minimum value of x2+y2\displaystyle x^2+y^2

I've been using Lagrange Multiplier but can't get the answer, is there any inequality theorem I could use?

#Inequality

Note by Natasha Andriani
5 years, 10 months ago

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Comments

Those equation can be expressed as xy(x2+y2)((x2+y2)23x2y2)1+x3y3=5\frac{xy(x^2+y^2)((x^2+y^2)^2-3x^2y^2)}{1+x^3y^3}=5 Stuck here. I'll add if I have something.

Fariz Azmi Pratama - 5 years, 10 months ago

That's an interesting question. Any idea what the minimum value is?

Calvin Lin Staff - 5 years, 10 months ago

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Minimum value?

Natasha Andriani - 5 years, 10 months ago

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Wolfram is giving 2.19032\approx 2.19032 as minimum value at x=y1.0465x = -y \approx 1.0465.

Krishna Sharma - 5 years, 10 months ago

Friend try this,

Let xy=txy = t t(x6+y6)t5+1=5t(x6+y6)=5t5+5x6+y6=5t4+5t\frac { t({ x }^{ 6 }+{ y }^{ 6 }) }{ { t }^{ 5 }+1 } =5\\ t({ x }^{ 6 }+{ y }^{ 6 })=5t^{ 5 }+5\\ { x }^{ 6 }+{ y }^{ 6 }=5{ t }^{ 4 }+\frac { 5 }{ t }

Now using Newtonian Sum you may find the value of x6+y6x^{6}+y^{6} in terms of xx and yy you may find the answer then.

Department 8 - 5 years, 10 months ago
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