Let ΔABC be a right angled triangle with ∠B=900. Let BD be altitude from B on to AC. Let P,Q and I be incenters of triangles ΔABD,ΔCBD and ΔABC respectively. Show that the circumcenter of triangle ΔPIQ lies on the hypotenuse AC.
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Confident on the 4th, Ok with the 2nd and 6th(?), bashed up the third. How did you answer the sixth? My answer concluded that even 9 integers would suffice, found a problem with that.
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@Sreejato Bhattacharya @megh choksi
How did your paper go?
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I solved 2, messed up the functional equation >.<. And my proof for Q2 had quite a bit of hand waving, so can't really expect full marks for it.
How did yours go?
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Confident on the 4th, Ok with the 2nd and 6th(?), bashed up the third. How did you answer the sixth? My answer concluded that even 9 integers would suffice, found a problem with that.
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i solved this question by using coordinate geometry, taking B as the origin. This year paper was a bit easier than last year except problem 5