Integral

i have a math problem : Question :

consider the integral expression in x

P=x^3+x^2+ax+1

where a is a rational number. at a = (...........) the value of P is a rational number for any x which satisfies the equation x^2+2x-2=0 , and in this case the value of P is (.........)

please help me in answering the question on its points thak you for your help

Note by Fadlan Semeion
8 years, 1 month ago

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Comments

If x2+2x2=0x^2+2x-2=0, then x2=2x+2x^2=-2x+2. Also, (x2+2x2)(x2)=x36x+4=0(x^2+2x-2)(x-2)=x^3-6x+4=0 so that x3=6x4x^3=6x-4.

If you substitute these in to PP, you get the expression in terms of only the first degree of xx: P=x3+x2+ax+1=(6x4)+(2x+2)+ax+1=(a+4)x1P=x^3+x^2+ax+1=(6x-4)+(-2x+2)+ax+1=(a+4)x-1.

You can see that by making a=4a=-4, PP will be rational (specifically, PP will equal 1-1). Note that no other rational value of aa works because (a+4)x1(a+4)x-1 would be a nonzero rational number (a+4a+4) times an irrational number (xx) minus a rational number (1-1), which would be irrational.

Ryoma Canastra - 8 years, 1 month ago

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from what (x-2) ?

Fadlan Semeion - 8 years, 1 month ago

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Sorry that I didn't explain that. I chose to multiply x2+2x2x^2+2x-2 by x2x-2 because that introduces an x3x^3 term (so that you can make the substitution) and because the result doesn't have an x2x^2 term (which would get in the way in the substitution, although even if there were an x2x^2 term you could use x2=2x+2x^2=-2x+2 to reduce the second degree to first degree).

Ryoma Canastra - 8 years, 1 month ago

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@Ryoma Canastra oh, i understand. i have other some math problem

this problem :

consider two conditions x^2-3x-10<0 and |x-2|<a ona real number x, where a is a positive real number.

(1) necessary and sufficient condition for x^2-3x-10<0 that (......)<x<(......)

(2) the range of values of a such that |x-2|<a is necessary condition for x^2-3x-10 is (......)

(3) the range of values of a such that |x-2|<a is sufficient condition for x^2-3x-10 is (......)

Fadlan Semeion - 8 years, 1 month ago
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