Interesting Comibnatorics problem.

The number of ways in which 9 boys and 5 girls can be arranged in two buses each having numbered seats, three in the front and five at the back such that at least four girls should always be together is ?

This was a question in an entrance exam that i found interesting and thought i should share.

#Combinatorics #MathProblem #Math

Easy Math Editor

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Comments

Kinda awarkd. 14 people, (3+5)x2 = 16 seats. This is kinda weird for me. And what's the front and the back? Is it interact with the number of girls? (Like 3 girls in the front and 1 in the back is OK or not?)

Kawaii Kuma - 7 years, 6 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$