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@Ashwin K
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Hmmm, yes we can, by assuming your last digit is already given, then you can make up any equation as you like. But I doubt any of these identity are useful, because it is too specific and are not applicable in the first place.
@Pi Han Goh
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It is magical number because we consider base 10 in our number system and thus last number '9' has to be Special. In general, last digit in that number system will carry special properties.
@Pi Han Goh
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There are interesting properties on it buddy. This is not my judgement. I think I am not convincing you. Just Google it for yourselves and check.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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Comments
I assume that a is a single digit positive integer and b is a non-negative single digit integer, then obviously b=9 and so your equation holds true.
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Yes..I considered only 2 digit numbers. I need to know how it works!
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After you know that b=9, what happens when you substitute b=9 into the equation ab+a+b=10a+b?
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For instance a =1, the equation becomes 1*9 + 1 + 9 = 19 = 10(1) + 9 = 19.
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a=2,3,…,9, but that is tiresome.
You can do that as well forI asked you to substitute b=9 alone only, nothing else. What happens to the equation ab+ab+b=10a+b after you substitute b=9?
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application of divisibility rules.
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