(tanx)2=(sinx)2+(sinx)4+(sinx)6+(sinx)8+⋯ \large { \left( \tan { x } \right) }^{ 2 }={ \left( \sin { x } \right) }^{ 2 }{ +\left( \sin { x } \right) }^{ 4 }+{ \left( \sin { x } \right) }^{ 6 }+{ \left( \sin { x } \right) }^{ 8 }+\cdots (tanx)2=(sinx)2+(sinx)4+(sinx)6+(sinx)8+⋯
Prove the trigonometric identity above.
Note by Joel Yip 5 years, 3 months ago
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2^{34}
a_{i-1}
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\sin \theta
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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