Interval

X^2<5

Note by Paras Queen
7 years, 7 months ago

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Comments

x2<5x25<0x^2 < 5 \rightarrow x^2 - 5 < 0

Δ=02451=20\Delta = 0^2 -4 \cdot -5 \cdot 1 = 20

x=0±202x= \frac{0 \pm \sqrt20}{2}

x1=252=5x_1 = \frac{2\sqrt5}{2} = \sqrt5

x2=252=5x_2 = \frac{-2\sqrt5}{2} = -\sqrt5

(xR/5<x<5x \in\mathbb{R} / -\sqrt5< x < \sqrt5)

Gabriel Merces - 7 years, 7 months ago

x<(5)^1/2

shaheed vh - 7 years, 7 months ago

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Not necessarily. There's more to it.

Daniel Leong - 7 years, 7 months ago
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