Say you have and and .
I observed that these two curves need not intersect, for example with and never intersecting each other.
I also observed that a function can either have one, two, or three intersections with its inverse, but I was unable to find a function which has more than 3 intersection points with its inverse.
How would I prove or disprove the hypothesis that an elementary function and its intersection can only have up to 3 intersection points? Any counterexamples are appreciated!
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Consider f(x)=x.
Note that g(x)=f−1(x)=x=f(x).
So, there are infinitely many intersections!
Good solution. I am aware of the infinite intersections solution, but does anyone have any functions which have 4 or more intersections with their inverse (but not an infinite number of intersections)?
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Consider, over any finite interval say X, f(x)=x+sinx.
Over the interval X there are finitely many intersections. The exact number depends on X itself. But you can have any finite number of intersections.
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Nice solution
At first, I was unsure of how to find the inverse of that function, so I decided to graph it to verify your claim and you're right!
http://www.wolframalpha.com/input/?i=find+inverse+of+f(x)+%3D+x%2Bsin(x)